303.range-sum-query-immutable

Statement

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Metadata

• Link: 区域和检索 - 数组不可变
• Difficulty: Easy
• Tag: 设计 数组 前缀和

给定一个整数数组  nums，处理以下类型的多个查询:

1. 计算索引 left 和 right （包含 left 和 right）之间的 nums 元素的 和 ，其中 left <= right

实现 NumArray 类：

• NumArray(int[] nums) 使用数组 nums 初始化对象
• int sumRange(int i, int j) 返回数组 nums 中索引 left 和 right 之间的元素的 总和 ，包含 left 和 right 两点（也就是 nums[left] + nums[left + 1] + … + nums[right] )

 

示例 1：

输入：
["NumArray", "sumRange", "sumRange", "sumRange"]
[[[-2, 0, 3, -5, 2, -1]], [0, 2], [2, 5], [0, 5]]
输出：
[null, 1, -1, -3]
解释：
NumArray numArray = new NumArray([-2, 0, 3, -5, 2, -1]);
numArray.sumRange(0, 2); // return 1 ((-2) + 0 + 3)
numArray.sumRange(2, 5); // return -1 (3 + (-5) + 2 + (-1)) 
numArray.sumRange(0, 5); // return -3 ((-2) + 0 + 3 + (-5) + 2 + (-1))

 

提示：

• 1 <= nums.length <= 104
• -105 <= nums[i] <= 105
• 0 <= i <= j < nums.length
• 最多调用 104 次 sumRange 方法

Metadata

• Link: Range Sum Query - Immutable
• Difficulty: Easy
• Tag: Design Array Prefix Sum

Given an integer array nums, handle multiple queries of the following type:

1. Calculate the sum of the elements of nums between indices left and right inclusive where left <= right.

Implement the NumArray class:

• NumArray(int[] nums) Initializes the object with the integer array nums.
• int sumRange(int left, int right) Returns the sum of the elements of nums between indices left and right inclusive (i.e. nums[left] + nums[left + 1] + … + nums[right]).

 

Example 1:

Input
["NumArray", "sumRange", "sumRange", "sumRange"]
[[[-2, 0, 3, -5, 2, -1]], [0, 2], [2, 5], [0, 5]]
Output
[null, 1, -1, -3]
Explanation
NumArray numArray = new NumArray([-2, 0, 3, -5, 2, -1]);
numArray.sumRange(0, 2); // return (-2) + 0 + 3 = 1
numArray.sumRange(2, 5); // return 3 + (-5) + 2 + (-1) = -1
numArray.sumRange(0, 5); // return (-2) + 0 + 3 + (-5) + 2 + (-1) = -3

 

Constraints:

• 1 <= nums.length <= 104
• -105 <= nums[i] <= 105
• 0 <= left <= right < nums.length
• At most 104 calls will be made to sumRange.

Solution

Python 3

from typing import List


class NumArray:
    def __init__(self, nums: List[int]):
        self.sum = []
        self.sum.append(0)
        for a in nums:
            self.sum.append(self.sum[-1] + a)

    def sumRange(self, left: int, right: int) -> int:
        return self.sum[right + 1] - self.sum[left]


# Your NumArray object will be instantiated and called as such:
# obj = NumArray(nums)
# param_1 = obj.sumRange(left,right)

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最后更新: October 11, 2023