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374.guess-number-higher-or-lower

Statement

Metadata

猜数字游戏的规则如下:

  • 每轮游戏,我都会从 1 到 n 随机选择一个数字。 请你猜选出的是哪个数字。
  • 如果你猜错了,我会告诉你,你猜测的数字比我选出的数字是大了还是小了。

你可以通过调用一个预先定义好的接口 int guess(int num) 来获取猜测结果,返回值一共有 3 种可能的情况(-11 或 0):

  • -1:我选出的数字比你猜的数字小 pick < num
  • 1:我选出的数字比你猜的数字大 pick > num
  • 0:我选出的数字和你猜的数字一样。恭喜!你猜对了!pick == num

返回我选出的数字。

 

示例 1:

输入:n = 10, pick = 6
输出:6

示例 2:

输入:n = 1, pick = 1
输出:1

示例 3:

输入:n = 2, pick = 1
输出:1

示例 4:

输入:n = 2, pick = 2
输出:2

 

提示:

  • 1 <= n <= 231 - 1
  • 1 <= pick <= n

Metadata

We are playing the Guess Game. The game is as follows:

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I will tell you whether the number I picked is higher or lower than your guess.

You call a pre-defined API int guess(int num), which returns three possible results:

  • -1: Your guess is higher than the number I picked (i.e. num > pick).
  • 1: Your guess is lower than the number I picked (i.e. num < pick).
  • 0: your guess is equal to the number I picked (i.e. num == pick).

Return the number that I picked.

 

Example 1:

Input: n = 10, pick = 6
Output: 6

Example 2:

Input: n = 1, pick = 1
Output: 1

Example 3:

Input: n = 2, pick = 1
Output: 1

 

Constraints:

  • 1 <= n <= 231 - 1
  • 1 <= pick <= n

Solution

# The guess API is already defined for you.
# @param num, your guess
# @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
# def guess(num: int) -> int:

from bisect import bisect_left


class Solution:
    def guessNumber(self, n: int) -> int:
        return bisect_left(range(n + 1), 0, 1, key=lambda x: -guess(x))

最后更新: October 11, 2023
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